Reply to Create new function for a select statement - TIA

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Posted by Dekka-X on 12/08/06 20:03

I want to call the following query from a function :

$sql2 = "SELECT * from session limit 1";
$result_thread = mysql_query($sql2, $conn);

while ($row3 = @mysql_fetch_array($result_thread)){
$sthread=$row3['thread'];
$slevel=$row3['level'];
}


The above code works fine in the program.

When I create a function I get the error:
Warning: mysql_query(): supplied argument is not a valid MySQL-Link
resource


The function code I was trying to use is here. (bonus points for
telling me what idiotic mistake I'm making) >>>.

function search_session(){
$sql2 = "SELECT * from session limit 1";
$result_thread = mysql_query($sql2, $conn);

while ($row3 =
@mysql_fetch_array($result_thread)){
$sthread=$row3['thread'];
$slevel=$row3['level'];
return $sthread;
return $slevel;
}
}

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