Posted by Jason Barnett on 06/24/05 17:02

Robert Cummings wrote:
....
>
>
> There's a difference between a reference to a reference and a copy of a
> reference *hehehe*.
>
> Cheers,
> Rob.

Dear diary: jackpot!

Now that makes sense. And am I correctly filling in the blanks when I
guess that $foo3 = $aObj is merely copying the reference instead of
referencing the reference? I probably could have written that more
clearly, but I think you get what I'm saying.

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