Posted by Robert Cummings on 06/24/05 18:49

On Fri, 2005-06-24 at 10:02, Jason Barnett wrote:
> Robert Cummings wrote:
> ...
> >
> >
> > There's a difference between a reference to a reference and a copy of a
> > reference *hehehe*.
> >
> > Cheers,
> > Rob.
>
> Dear diary: jackpot!
>
> Now that makes sense. And am I correctly filling in the blanks when I
> guess that $foo3 = $aObj is merely copying the reference instead of
> referencing the reference? I probably could have written that more
> clearly, but I think you get what I'm saying.

Yeah, *grin*. And on that note, there are times when you will actually
want $foo = &new SomeClass(); versus $foo = new SomeClass(); since
assigning by reference will break any previous references -- something I
forgot to mention to Matthew Weier when he challenged the relevance of
the snippet I sent.

Cheers,
Rob.
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