Posted by MS on 01/11/07 14:51

> HI there.
>
> Ive got a quick question.
>
> How do I have a select box show a particular value.
>
> Same as a previous post but I dont think it got answered
>

I use the following function....

// $name = the field name
// $type = "selection" || "checkbox" || "radio", the type of field you want
to display the data in.
// $class = the class to use
// $listarray = array("id","value")
// $selected = Which item is selected within the list in the format
"int,int,int" for radio and in the format "int" for selection & checkbox

// So just by changing the $type in the calling function you can have the
data displayed in 3 ways.

function getFormInput($name,$type,$class,$listarray,$selected=""){
$res = "";
if($type == "selection"){
$res .= "<select name='".$name."' class='".$class."'>\n";
for ($i=0;$i <= count($listarray);$i++) {
$sel = ($selected == $listarray[$i]['id']? " selected" : "");
$res .= "<option
value='".$listarray[$i]['id']."'$sel>".$listarray[$i]['name']."</option>\n";
}
$res .= "</select>\n";
}elseif($type == "checkbox"){
$selsplit = explode(',',$selected);
for ($i=1;$i <= count($listarray);$i++) {
$sel = (in_array($listarray[$i]['id'],$selsplit)? " checked" : "");
$res .= "<input type='checkbox' name='".$name."[".$i."]'

value='".$listarray[$i]['id']."'$sel>".$listarray[$i]['name']."<br>\n";
}
}elseif($type == "radio"){
for ($i=1;$i <= count($listarray);$i++){
$sel = ($listarray[$i]['id'] == $selected) ? " checked" : "";
$res .= "<input type='radio' name='".$name."'

value='".$listarray[$i]['id']."'$sel>".$listarray[$i]['name']."<br>\n";
}
}
return $res;
}


Hope that helps

MS
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