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Posted by Erwin Moller on 01/24/07 09:26
Schmidty wrote:
> So if I do a $_SERVER['PHP_SELF'] in a function within a class that
> will end the execution of that class and restart the same script? Do I
> need to do all processing in a script before I display a page that will
> have a $_SERVER['PHP_SELF'] action? Thanks for the help...
>
> Schmidty
Hi,
Please don't toppost. It destroys the order of the conversation.
$_SERVER['PHP_SELF'] is just a string that contains the script that is being
executed.
I do not understand what 'doing a $_SERVER['PHP_SELF'] in a function' means.
But it will most probably NOT terminated the execution of the script.
exit(); does.
You must clearly see the difference between the server and the client
(browser).
Your script produces a form that will be send back to the client (=browser).
Then your script ends.
The form action in your example posts back to the same script (because you
used the target for the action $_SERVER['PHP_SELF']), so if anybody presses
submit, that form will be posted, and hence the same script will be
executed as before.
But the server or PHP couldn't care less, and thinks of it as just another
call to that script.
http-protocol is stateless, this means that NO lasting connection is build
between the client and the server. To overcome this you must use sessions.
And as Jerry said: connections to a database are NOT fit to store in a
session because PHP destroys all existing connections when the script ends.
So you'll have to rebuild your connection each invocation of a script that
needs a database.
Hope this helps.
Regards,
Erwin Moller
>
> On Jan 23, 4:54 pm, Jerry Stuckle <jstuck...@attglobal.net> wrote:
>> Schmidty wrote:
>> > If you do a page reload with $_SERVER['PHP_SELF'] will your program
>> > lose a mysqli connection upon the reload of the page? Would this code
>> > work? I need to know how to carry over a connection between methods as
>> > I am new to OOP? Thanks...
>>
>> > Example; ========================================
>> > <?php
>> > // webpage
>> > $newsignon = new newuser();
>> > logon();
>>
>> > if (isset($_POST['submit'])){
>> > $newsignon = query("SELECT name, password FROM
>> > database");
>> > }
>> > ?>
>> > <?php
>> > // class newuser
>>
>> > class newuser {
>> > public $name;
>> > private $passwd;
>> > private $mysqli;
>>
>> > function __construct(){
>> > include('dbconn.php');
>> > $mysqli = new mysqli($dbnet, $dbuser, $dbpass, $dbname);
>> > if (mysqli_connect_errno()){ printf("Can't connect to MySQL
>> > Server. Errorcode: %s\n", mysqli_connect_error());
>> > exit;
>> > }
>> > $this->mysqli = $mysqli; // is this right?
>> > } //end constructor
>>
>> > function query($query){
>> > if ($result = $this->mysqli->real_query($query)){
>> > $result = $this->mysqli->store_result();
>> > if($this->mysqli->error) { echo "ERROR with mysqli stored
>> > procedure";}
>> > } // end if
>>
>> > } // end function
>>
>> > function logon(){
>> > echo "<form action='".$_POST['PHP_SELF']."' method='post' >";
>> > // Would this work?
>> > echo "<input type='text' name='user' /><br /><input
>> > type='password' name='passwd' />";
>> > echo "<input type='submit' value='submit' />";
>>
>> > } // end function
>>
>> > } //end classSchmidty,
>>
>> As I explained in comp.database.mysql, you can't. Once a page's
>> processing is completed, all connections (and objects) are released.
>>
>> You can keep information like user ids, etc. in the $_SESSION variable,
>> but not the connection. Even if you could keep the connection info in
>> there, the connection itself will be closed.
>>
>> Each page is it's own little program. Any external resources opened by
>> it are closed at the end of the page processing.
>>
>> --
>> ==================
>> Remove the "x" from my email address
>> Jerry Stuckle
>> JDS Computer Training Corp.
>> jstuck...@attglobal.net
>> ==================
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