Reply to Re: date problem

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Posted by Jasper Bryant-Greene on 06/29/05 04:28

Firstly, this shouldn't be in the PHP list, as you're asking for help
with SQL.

Mario netMines wrote:
> carrental_from (datetime field)
> carrental_to (datetime field)
> carrental_price (datetime field) [rates are per hour]

carrental_price shouldn't be a datetime field, as it isn't a datetime value.

> The values I have are like:
> 0000-00-00 00:00:00,0000-00-00 07:00:00,10 (all year around 00:00-07:00)
> 0000-00-00 07:00:00,0000-00-00 00:00:00,20 (all year around 07:00-00:00)
> 2005-12-22 07:00:00,2006-01-02 00:00:00,15 (christmas period 00:00-07:00)
> 2005-12-22 00:00:00,2006-01-02 07:00:00,25 (christmas period 07:00-00:00)
>
> The user selects dates ($from - $to) to rent a car and he gets the price
> accordingly.
> I can do a (($to-$from)/60/60) and get the total number of hours but
> depending on the date and time you get a different result. Can anyone
> help with the SQL?

Read up on the MySQL DATEDIFF() function, if you are using MySQL. Other
DBMSs should have an equiv. function.

Jasper

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