Reply to Passing mysql table names to php functions?

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Posted by kennthompson on 02/27/07 14:25

Trouble passing mysql table name in php. If I use an existing table
name already defined everything works fine as the following script
illustrates.

<?php
function fms_get_info()
{
$result = mysql_query("select * from $tableInfo") ;
for ($i = 0; $i < mysql_num_rows($result); $i++)
{
/* do something */
}
}

/* Main */
fms_get_info();


But it won't work if I pass a variable table name to the function.


<?php
function fms_get_info($tableName)
{
$result = mysql_query("select * from $tableName") ;
for ($i = 0; $i < mysql_num_rows($result); $i++)
{
/* do something */
}
}

/* Main */
fms_get_info($tableInfo);


I need to use the same function to gather information from multiple
tables at will without creating a different function for each possible
mysql database table by name. I thought this would be easy, but I
have failed at several tries.

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