Posted by Tyno Gendo on 04/30/07 16:43

ZeldorBlat wrote:
> The object is automatically destroyed when nothing is referencing it.
> When you assign the second instance to $x, there is nothing left
> referencing the first instance.
>
> There was another thread on this subject recently:
> <http://groups.google.com/group/comp.lang.php/browse_frm/thread/
> 7046181c4c507263/3e766edeeebbd5f5#3e766edeeebbd5f5>
>

At the risk of starting the $a++ thread again ... hehe

I believe that will be why $a = $a++; doesn't work.

The PHP manual should say $a++ "Returns value of $a" not "Returns $a..."
which to me infers it returns itself as a reference and the ++ should work.

But, returns value of a, hence $a overwrites itself, and the ++ tries to
take effect on the original which now has no references so doesn't exist.

Umm... Monday afternoon.. I'm bored and perplexed at the same time.

I don't think that helped you, sorry. I'll get my coat.

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