Posted by woger151 on 05/01/07 01:03

On Apr 30, 10:43 am, ZeldorBlat <zeldorb...@gmail.com> wrote:
> On Apr 30, 10:35 am, woger...@jqpx37.cotse.net wrote:
>
>
>
>
>
> > If I write
> > $x = new some_class($init_data1);
> > and then
> > $x = new some_class($init_data2);
>
> > does the first object (constructed with $init_data1) get destroyed, or
> > do I have to call unset() for that? And am I guaranteed that after
> > the second call the value of $x will be as if the first call was never
> > made?
>
> > I tried using var_dump within a for loop to see what was happening
> > (ie, using "new" and assigning it to the same variable name everyt
> > ime), and in the printout I get stuff like
> > object(some_class)#1
> > alternating with
> > object(some_class)#2
>
> > If I call unset(), I don't get the #2. I'm assuming that (in the case
> > I don't call unset()) PHP is destroying the variable every other
> > iteration due to some kind of garbage collection algorithm. And the
> > "#1" and "#2" refer to the actual object being referenced.
>
> > TIA
>
> The object is automatically destroyed when nothing is referencing it.
> When you assign the second instance to $x, there is nothing left
> referencing the first instance.
>
> There was another thread on this subject recently:
> <http://groups.google.com/group/comp.lang.php/browse_frm/thread/
> 7046181c4c507263/3e766edeeebbd5f5#3e766edeeebbd5f5>- Hide quoted text -
>
> - Show quoted text -

Great---thanks for the informative reply.

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