Reply to Re: 'nested conditional' that can identify parent page?

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Posted by shimmyshack on 05/13/07 02:20

On 13 May, 00:31, Alan Jones <a...@jalanjones.com> wrote:
> On 12 May 2007 08:48:01 -0700, shimmyshack <matt.fa...@gmail.com>
> wrote:
>
>
>
> >On May 11, 11:40 pm, Alan Jones <a...@jalanjones.com> wrote:
> >> Hello everyone, any help would be greatly appreciated. :)
>
> >> What I'm trying to do may not be advisable, but here goes...
>
> >> I want a page named signature.php to appear conditionally as
> >> an include within another include so that it will, for example,
> >> appear in index.php but not in other result pages that use the
> >> same top level include.
>
> >> The method would need to determine what page it is inside of
> >> during each given instance. I guess something like...
>
> >> if page is index.php then include file else do nothing
>
> >> A 'nested conditional' seems obvious but I don't know how to
> >> create an argument that checks the result page file name or
> >> otherwise id's that parent page.
>
> >> Obviously, I'm new to PHP and my understanding of basic
> >> programming is very limited. I'm also new to the group. I hope
> >> to learn quickly, and I look forward to helping others in the
> >> future.
>
> >make three php pages,
> >each containing the following
> >apart from the last line
> ><?php
> >echo '<pre>';
> >echo "me: " . __FILE__;
> >echo $_SERVER["REQUEST_URI"] . "\n";
> >echo $_SERVER["SCRIPT_NAME"] . "\n";
> >echo $_SERVER["PHP_SELF"] . "\n";
> >echo $_SERVER["SCRIPT_FILENAME"] . "\n";
> >echo "\n\n";
> >include ( '2.php' );
> >?>
> >inside 2.php the last line should be 3.php
> >and inside 3.php theres no include
>
> >you will see that __FILE__ always contains the name of the script it
> >is in, whether than is included in something else or not.
> >whereas $_SERVER['SCRIPT_FILENAME'] doesnt change, it returns 1.php
> >because that is the script your are executing, so you can use it to
> >find the name of the file that includes the others.
> >your basic script would be
> >if( basename($_SERVER['SCRIPT_FILENAME'])=='index.php' )
> >{
> > include( 'signature.php' );
> >}
> >however if you change your server setup this might not always work, as
> >you said before hard coding things like this is generally not a good
> >idea. Instead look at the architecture you are building and see if you
> >cant handle the whole thing in one function somewhere centrally
> >located say in /private/appname/functions
> >this way your life is easier later on.
> >hope that helps.
>
> Thank you very much for the help. :) I'll give your recommendation
> a run thru, but is there a way to make basename, or a similar
> function, simply return the filename of the parent page; the page
> the include is in? Thanks again, I really appreciate any help I can
> get.

basename($_SERVER['SCRIPT_FILENAME']);
does exactly that, try it.

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