Posted by Denis Gerina on 06/05/07 10:33

mypetprogrammer@gmail.com wrote:
> On Jun 4, 5:53 pm, Denis Gerina <denisREMOVET...@cced.ba> wrote:
>> vinnie wrote:
>>> it only displays the name, but the last name and the address seems not
>>> to exist! why?
>>> <?php
>>> @ $db=mysql_pconnect('host', 'UserID', 'PWD');
>>> if (!$db)
>>> {
>>> echo 'conneciton eror';
>>> exit;
>>> }
>>> else
>>> {
>>> echo 'connection on!';
>>> }
>>> mysql_select_db('list');
>>> $query="select * from index";
>>> $result=mysql_query($query);
>>> $num_results=mysql_num_rows($result);
>>> if ($num_results == 0)
>>> {
>>> echo'<br><br>nothing to dispaly';
>>> }
>>> else
>>> {
>>> echo'<br><br>here are the results: '.$num_results;
>>> }
>>> for ($i<0; $i<$num_results; $i++)
>>> {
>>> $row=mysql_fetch_array($result);
>>> echo '<br>name: ';
>>> echo htmlspecialchars(stripslashes($row['name']));
>>> echo '<br>last name: ';
>>> echo htmlspecialchars(stripslashes($row['last']));
>>> }
>>> ?>
>> You don't seem to be printing address anywhere. As for last name, check
>> the name of the column in your table (index).
>>
>> And, to avoid notices, the code
>>
>> for ($i<0; $i<$num_results; $i++)
>>
>> should be
>>
>> for ($i=0; $i<$num_results; $i++)
>>
>> Although I would probably write something like
>>
>> while ($row = mysql_fetch_array($result))
>> {
>> ...
>>
>> }
>
> See, and I would avoid the inevitable out of bounds on that with:
> while( ($row = mysql_fetch_array($result)) != null)
> {
>
> So as not to be operating on a null on the last iteration of the loop.
> Agree with the while, though.
>
> ~A!
>

Interesting. Do explain, please, in light of the docs.


http://www.php.net/mysql_fetch_array

Returns an array of strings that corresponds to the fetched row, or
FALSE if there are no more rows.

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