Posted by petersprc on 07/15/07 03:53

Your query can fetch the URL by doing a join:

select a.x,y.z,b.url from a, b where a.x = b.x

Then when you print the results:

echo "<a href=\"{$url}\">$a</a>";

On Jul 14, 10:23 pm, thanos <inlov...@hotmail.com> wrote:
> Hello,
>
> Im in a real bind here trying to figure out a solution to my problem.
>
> I have a table which has paging. However, since the data is coming
> from a database, I would like for the values in one of the columns to
> also include hyperlinks.
>
> Here is my sample code for extracting and displaying the data. Now I
> would like to display col1 as a hyperlink, Col1 is just two letter
> symbol char(2), however each symbol has its own unique hyperlink. I
> have the hyperlink addresses saved in the database as well. Any ideas
> would be extremely helpful! Thanks Al
>
> ///create query
> $query = "SELECT col1, col2, col3 FROM table1 ";
>
> ///store results of query
> $result = mysql_query($query . $pagingQuery) or die('Error, query
> failed');
>
> //display query results
> echo '<table width="100%"><tr><td>column1</td><td> column2</td>
> <td>column3</td></tr>';
> while(list($col1, $col2, $col3) = mysql_fetch_array($result))
> {echo "<tr><td>$col1</td><td>$col2</td><td>$col3</td></tr>";}
>
> echo '</table>';

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