Posted by Rik on 07/31/07 00:46

On Tue, 31 Jul 2007 02:38:04 +0200, Jerry Stuckle =

<jstucklex@attglobal.net> wrote:
> I take this back - the result of the operation is unpredictable. That=
's =

> because:
>
> $rank[$i] =3D trim($rank[$i++]);
>
> $rank[$i++]
>
> is evaluated as $rank[$i]. However, when
>
> $rank[$i]
>
> is evaluated, does it use the old or the new version of $i?

This is indeed dubious. Which of the '[' gets evaluated first? Allthough=
, =

left-associtivity might indicate the first one should be evaluated first=
=

(PHP4 behaviour).

However, for:

$array[$i] =3D $i++;

Precedence as defined should kick in clearly. The '[' isn't in the table=
=

just for show.

> The bottom line: don't change a value and use it in the same statement=
.. =

> Results are unpredictable.

And makes for more readable code indeed. However, if I read the =

documentation I fully expect the PHP4 result from my example, not the PH=
P5 =

one...
-- =

Rik Wasmus

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