Reply to Re: Help with if... else - please

Your name:

Reply:


Posted by Thijs de Zoete on 08/27/07 18:49

Steve schreef:
> Can anyone help me with this code. What I want to do is check the DB and if
> there is no result returned (by checking the date field) I want to echo "no
> shows".
>
> But no matter what I do it seems to blow through ANY if else statements I try
> and if there are dates it shows them if not it is just blank.
>
> is it as simple as my code being screwed up or am i missing something else?
>
> Steve
>
>
> while($band = mysql_fetch_array($result, MYSQL_ASSOC))
> {
>
> $change_to_time = strtotime($band[date]);
> $newdate = date('m.d.Y', $change_to_time);
>
>
> if (empty($band[date])) {
> echo "No shows on the calendar.";
> }
>
> else {
> echo "<div id=\"line1\">$newdate - $band[venue]</div>";
> echo "<div id=\"line2\">$band[street] $band[city], $band[state] - <a href =
> \"http://maps.google.com/maps?q=$band[street]+$band[city]+$band[state]\">Map</
> a></div>";
> echo "<div id=\"line3\">$band[notes]</div>";
> echo "<div id=\"line4\">Time - $band[time], Cost - $band[cost]</div>";
> echo "<hr />";
> }
>
> }
>
>

First of all i'd say put a break in the loop if its empty:
if (empty($band)) {
echo "No shows on the calendar.";
break;
}

And i wouldn't see any problems with the if, But maybe use '' 's on
array values, e.g.:
$band['date'] instead of $band[date]...

Hope that helps some

[Back to original message]


Удаленная работа для программистов  •  Как заработать на Google AdSense  •  England, UK  •  статьи на английском  •  PHP MySQL CMS Apache Oscommerce  •  Online Business Knowledge Base  •  DVD MP3 AVI MP4 players codecs conversion help
Home  •  Search  •  Site Map  •  Set as Homepage  •  Add to Favourites

Copyright © 2005-2006 Powered by Custom PHP Programming

Сайт изготовлен в Студии Валентина Петручека
изготовление и поддержка веб-сайтов, разработка программного обеспечения, поисковая оптимизация