Reply to Re: Passing by Reference

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Posted by gosha bine on 09/11/07 12:52

On 11.09.2007 14:20 Sanders Kaufman wrote:
> I think I finally get the idea of passing by reference, but I'm
> struggling with the syntax and grammar of it.
>
> I've got an object and I want to send it to a function to have its
> properties modified like so:
>
> [code]
> class MyClass {
> var $a;
> function MyClass(){
> $this->a=0;
> }
>
> function fnClassify($oClass){
> $oClass->a = 1;
> return true;
> }
>
> $oMyClass = new MyClass();
> echo $oMyClass->a; // displays "0"
>
> $bSuccess = fnClassify($oMyClass);
> echo $oMyClass->a; // displays "1"
> [/code]
>
>
> Unfortunately, the syntax is wrong somehow. At some point, I should be
> passing a reference to, instead of the value of, $oMyClass - but I don't
> know where or how.
>
> Can someone help me out here?

In php4 you should prepend & to any variable or a function parameter
containing or refering to an object. Examples include:

function foobar(&$someObject)

$someObj = &new ClassName;

$someObj = &$anotherObj;

Every function that returns an object, should return by reference (use &
twice)

function &getObject() {
....
return &$someObjectVar;
}

Again, all this is needed only for php4. I can't think of a good reason
to use it.


--
gosha bine

makrell ~ http://www.tagarga.com/blok/makrell
php done right ;) http://code.google.com/p/pihipi

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