Posted by Steve on 09/22/07 18:43

<dkirkdrei@yahoo.com> wrote in message
news:1190475589.522207.39050@o80g2000hse.googlegroups.com...
> On Sep 22, 11:29 am, Jerry Stuckle <jstuck...@attglobal.net> wrote:
>> dkirkd...@yahoo.com wrote:
>> > On Sep 22, 10:40 am, gosha bine <stereof...@gmail.com> wrote:
>> >> dkirkd...@yahoo.com wrote:
>> >>> On Sep 22, 4:28 am, gosha bine <stereof...@gmail.com> wrote:
>> >>>> dkirkd...@yahoo.com wrote:
>> >>>>> I am having a bit of trouble trying to double up on slashes in a
>> >>>>> file
>> >>>>> path. What I am trying to do is very similar to the code below:
>> >>>>> <?
>> >>>>> $var = "\\wusais\Intranets\Intranets\fpdb\pdf\weinig\00505882.pdf";
>> >>>>> $new = preg_replace("\\", "\\\", "$var");
>> >>>>> ?>
>> >>>>> Code above produces the following error:
>> >>>>> Parse error: parse error, unexpected T_VARIABLE in
>> >>>>> c:\Inetpub\wwwroot
>> >>>>> \pages\replace.php on line 12
>> >>>>> In the end, $new needs to be:
>> >>>>> \\\\wusais\\Intranets\\Intranets\\fpdb\
>> >>>>> \pdf\\weinig\\00505882.pdf
>> >>>>> but it seems to be very difficult replacing slashes.
>> >>>>> Any help would be greatly appreciated
>> >>>> $var =
>> >>>> "\\wusais\\Intranets\\Intranets\\fpdb\\pdf\\weinig\\00505882.pdf";
>> >>>> echo strtr($var, array('\\' => '\\\\'));
>> >>>> note that initially $var actually contains only single slashes,
>> >>>> however
>> >>>> you must write each slash twice because of php escaping rules.
>> >>>> --
>> >>>> gosha bine
>> >>>> extended php parser ~http://code.google.com/p/pihipi
>> >>>> blok ~http://www.tagarga.com/blok-Hidequoted text -
>> >>>> - Show quoted text -
>> >>> These file paths are coming from a database, they are all windows
>> >>> paths and they reside on a company intranet so it is a "controlled"
>> >>> environment. Every file path is structured just like
>> >>> \\wusais\Intranets
>> >>> \Intranets\fpdb\pdf\weinig\00505882.pdf. For what I am trying to do,
>> >>> I
>> >>> have to double up on all of the slashes which is really being a pain.
>> >>> At this point, I believe I am going to try and explode the string to
>> >>> remove all the slashes and then reassemble it with the correct number
>> >>> of slashes.
>> >> This doesn't matter where the string comes from. The code I posted
>> >> above
>>
>> >> $var = strtr($var, array('\\' => '\\\\'));
>>
>> >> should work for the strings coming from the database as well.
>>
>> >> --
>> >> gosha bine
>>
>> >> extended php parser ~http://code.google.com/p/pihipi
>> >> blok ~http://www.tagarga.com/blok-Hide quoted text -
>>
>> >> - Show quoted text -
>>
>> > the code:
>>
>> > <?
>> > $var = "\\wusais\Intranets\Intranets\fpdb\pdf\weinig\00505882.pdf";
>> > echo strtr($var, array('\\' => '\\\\'));
>> > ?>
>>
>> > produces this:
>>
>> > \\wusais\\Intranets\\Intranets\\fpdb\\pdf\\weinig 05882.pdf
>>
>> > close but the end is still killing me...
>>
>> That's because your starting string is NOT VALID! See my post above.
>>
>> Get the string from the database and try parsing it. You'll get a much
>> different result.
>>
>> --
>> ==================
>> Remove the "x" from my email address
>> Jerry Stuckle
>> JDS Computer Training Corp.
>> jstuck...@attglobal.net
>> ==================- Hide quoted text -
>>
>> - Show quoted text -
>
> My problem is that the string coming from the database as variable
> with 2 slashes in the front and 1 slash between each directory. Once
> the variable comes from the db, I am passing it on to a javascript. If
> I pass the variable as is, the script will not work but if I double up
> on the slashes everything works fine. So, I have to take the file path
> that is coming out of the db and double up on the slashes. Using only
> php, everything works fine with the slashes the way they are.


gotcha...it's just hard to express for the purposes of posting here what
jerry would consider a *valid* string (whatever that means), so that we have
something to work with. is that about right?

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