Reply to I want to return a string to a wrapper from a subordinate stored procedure

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Posted by bobc on 09/27/07 19:36

Using SQL Server 2000...

I wrote a wrapper to call a sub proc (code provided below). The
intended varchar value returned in the output parameter of each proc
is a string implementation of an array.
(The string separates elements by adding a period after each value.
e.g. 1. 2. 3. 4. 5. etc., although my simplified example only creates
two elements.)
My vb.net calling code parses the returned string into individual
elements.

I TESTED BOTH PROCS FIRST:
The wrapper returns 'hello' when I test it by inserting
SELECT @lString='hello'
before the GO, so I believe it is called properly.

The sub_proc returns the "array" I want when I call it directly.

THE PROBLEM: When I call the wrapper, and expect it to call sub_proc,
it returns a zero.
In fact, when I assign a literal (like 'hello') to @lString in
sub_proc, 'hello' is not returned.
So the wrapper is not calling the sub_proc, or the sub_proc is not
returning an output value.
OR...I have read about some issues with OUTPUT string parameters being
truncated or damaged somehow when passed. I doubt this is the
problem, but I'm open to anything.

I want to use the wrapper because, when it's finally working, it will
call several sub_procs and
return several output values.

Any thoughts? Thanks for looking at it! - Bob

The Wrapper:
-----------------------------------------------------------------
CREATE PROCEDURE wrapper
@lString varchar(255) OUT
AS

EXEC @lString = sub_proc @CommCode, @lString OUT
GO
-----------------------------------------------------------------

The subordinate procedure:
-----------------------------------------------------------------
CREATE PROCEDURE sub_proc
@lString varchar(255) OUT

AS

DECLARE @var1 int,
@var2 int

SELECT @var1 =
(SELECT count(mycolumn)
FROM mytable
WHERE condition=1)

SELECT @var2 =
(SELECT count(mycolumn)
FROM mytable
WHERE condition=2)

/* If @var1 returns 5 and @var2 returns 7, Then @lString below would
be "5. 7." */

SELECT @lString = STR(@var1) + '.' + STR(@var7) + '.'
GO
-----------------------------------------------------------------

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