Posted by Shelly on 10/01/07 19:28

"dino d." <dinodorroco@yahoo.com> wrote in message
news:1191266023.643662.261490@19g2000hsx.googlegroups.com...
> Hi- I want to create a dynamic image with areas so that when the user
> clicks different areas, the user jumps to those pages. The problem
> is, I can't seem to figure out how to do this efficiently.
>
> Suppose I have a table,items in a database:
>
> itemid description count
>
> So, basically, I want to create an image that has 3 ovals,
> representing the top 3 occurring items (with the highest count) in
> this table. So, first, I create the image html:
>
> echo "<image src=genimage.php?items=$itemstring...
>
> So, here, I pass genimage a string that encodes the keys for the top 3
> occurring items. And in genimage, a query is created and called to
> get the descriptions and counts, and then displays those descriptions
> and counts in the ovals.
>
> The problem is, now I have to do this all over again to generate the
> area tags and corresponding jump URLs. Why? because I can only send
> the data in a GET string, since the image source has to be a url. So,
> I'm calling the identical query twice-once inside the image
> generation, and once in the area generation.
>
> I suppose I *could* get all the data once (the item descriptions and
> counts) and encode all of that and send that as a data string, but
> there has to be an easier way.
>
> Another suboptimal solution is to generate a temporary image and
> create img link to that image, but I'd rather keep these dynamic.
>
> So, is there a way create and then embed an image directly into a
> page? Or must I use a URL reference?
>
> In other words, what I'd like to do is something like:
>
>
> echo "<img src= THIS IMAGE STREAM I'M GENERATING RIGHT NOW...
>
> Any ideas on if this can be accomplished?
>
> Thanks,
> Dino

I have read this three times and
(a) I still can't figure out what you are trying to do and
(b) what problems your are having.

Shelly

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