Posted by Dan Trainor on 07/22/05 00:03

Dan Trainor wrote:
> Mike Johnson wrote:
>
>>From: Dan Trainor [mailto:info@hostinthebox.net]
>>
>>
>>
>>>Hello, all -
>>>
>>>I've been looking around for a function that would tell me if a $value
>>>in a $key=>$value array was empty, and I could not find one. So I
>>>decided to make my own. Even if I am re-inventing the wheel,
>>>I thought that the practice might be good for me.
>>>
>>>However, my function doesn't *quite* work, and I'm having a difficult
>>>time finding out why. The code is as follows:
>>>
>>>function findMissingVals($workingArray) {
>>> $newcount = count($workingArray);
>>> for ($i = 0; $i <= $newcount; $i++) {
>>> if (empty($workingArray['$i'])) {
>>> return 1;
>>> }
>>> }
>>>}
>>>
>>>So it takes in $workingArray as an array, runs a loop, checks $i, yada
>>>yada. The thing is, that sometimes the function does not
>>>return 1, even when it should.
>>>
>>>I was hoping some experienced eyes could take a gander at
>>>this and give me some pointers.
>>
>>
>>PHP doesn't eval code in single-quotes, so what you want to do is
>>simply:
>>
>>if (empty($workingArray[$i])) {
>> return 1;
>>}
>>
>>With the single-quotes, it's looking for the string $i as a key.
>>
>>HTH!
>>
>
>
>
> Hey there, Mike -
>
> Your tips were very helpful, thank you. I saw my error, but I am still
> having problems. Being somewhat novice to PHP, I think my error might
> very well just be in my implementation of the function, as follows:
>
> function findMissingVals($workingArray) {
> $newcount = count($workingArray);
> for ($i = 0; $i <= $newcount; $i++) {
> if (empty($workingArray[$i])) {
> return 1;
> }
> }
> }
>
> if (findMissingVals($vars)) {
> if (!$var1) { ?> hi1 <? };
> if (!$var2) { ?> hi2 <? };
> if (!$var3) { ?> hi3 <? };
> if (!$var4) { ?> hi4 <? };
> if (!$var5) { ?> hi5 <? };
> if (!$var6) { ?> hi6 <? };
> } else {
> echo "hi";
> }
>
>
> I never see "hi", even if I have an array as $vars as such:
>
> $vars = array("one","two","","four","five");
>
> so I'm a bit confused.
>
> If you wouldn't mind taking another few minutes here, I would greatly
> appreciate it.
>
> Thanks!
> -dant
>

Er, sorry about that -

I never see "hi" even if an array is set as such:

$vars = array("one","two","three","four","five");

but I do see "hi3" if I have an array set as such:

$vars = array("one","two","","four","five");

Thanks!
-dant

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