Reply to Re: print out variable name as well as its content

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Posted by Kye on 10/19/07 12:28

> That typically means you've added some code for debugging problems.
>
> There are settings in your php.ini file which should be different between
> development and production systems (i.e. display_errors), and some debug
> functions. And there are external debuggers.
>
> But there isn't a "debug mode" in the way you're thinking.

Would this include the classic things like mysql_error like in the below?

$result = mysql_query($query) or die ('Error in query: $query. '
..mysql_error());

--
Yours Sincerely
Kye

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