Reply to Re: include name from variable name? help?

Your name:

Reply:


Posted by Krustov on 12/03/07 00:04

A loop might a be idea if everything is a number .

$loopy=1;
while ($loopy<20)
{
if ($imagecat==$loopy) {$batman=$loopy . ".php"; include($batman);}
$loopy=$loopy+1;
}

The above code is untested and really just intended to get you started .


<comp.lang.php>
<>
<Sun, 2 Dec 2007 15:44:12 -0800 (PST)>
<bd28edd9-c1b5-4470-b158-1f54eb599c3e@e4g2000hsg.googlegroups.com>

> I am trying to generate an include name on an image gallery page from
> a variable name.
> By this I mean I already have a numeric value set the variable
> $imageCat.
>
> What I want to do is pull in an external include file using the
> variable as the file name. So if $imageCat is set to 2 I want to bring
> in 2.html ($imageCat.html).
>
> I can hard code each include request as such:
>
> {if $imageCat=="2"}
> {php}
> include ("2.php");
> {/php}
> {/if}
>
> But I am dealing with oodles of categories so this file would be huge.
> A dynamic option would be very cool but I just can't seem to get my
> syntax right.
>

[Back to original message]


Удаленная работа для программистов  •  Как заработать на Google AdSense  •  England, UK  •  статьи на английском  •  PHP MySQL CMS Apache Oscommerce  •  Online Business Knowledge Base  •  DVD MP3 AVI MP4 players codecs conversion help
Home  •  Search  •  Site Map  •  Set as Homepage  •  Add to Favourites

Copyright © 2005-2006 Powered by Custom PHP Programming

Сайт изготовлен в Студии Валентина Петручека
изготовление и поддержка веб-сайтов, разработка программного обеспечения, поисковая оптимизация