Reply to Re: Command

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Posted by Fred Atkinson on 01/14/08 01:59

On Sun, 13 Jan 2008 19:32:22 -0500, Daniel Ennis
<daniel@fanetworks.net> wrote:

>Did you try my solution? It should be alot quicker than the above
>method, but I did forget to ask, are their directories in the folder
>that shouldnt be counted?
>
>Thats a problem with the above example by thib also, file names without
>extensions wouldnt be counted.
>
>A sure fire way of doing it would be:
>
><?php
>$dir = './directory';
>function countfiles($dir = '.')
>{
> $count = 0;
> $dir = rtrim($dir,'/').'/';
> if(!is_dir($dir)) return false;
> foreach(new DirectoryIterator($dir) as $file)
> {
> if(is_file($dir.$file)) $count++;
> }
> return $count;
>}
>echo countfiles();
>?>
>
>Of course, this is PHP5, and if you dont have PHP5, you should be
>changing hosts :P Use these new SPL functions given to us for faster code!

That one worked. Yes, there is a subdirectory in the
directory in question and no it shouldn't be counted for what my
purposes are.

Is there any way to limit it to count .jpg files (I don't
see any screening in this example)? I want to return the number of
images in the directory (all of them are .jpg and will continue to be)
and not any text, html, php, or other types of files.

I'm surprised that PHP doesn't have functions built into it to
do this.

The site I am doing this on is running PHP version 5.2.5.

Regards,



Fred

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