Posted by Jochem Maas on 03/04/05 13:37

anirudh dutt wrote:
> On Fri, 4 Mar 2005 17:41:01 +0800, yangshiqi <yangshiqi@3721.com> wrote:
>
>>class DebugHelper
>>{
>> var $_str;
>> function do($string)
>> (
>> //here I want to know which class called this function do to
>>trace the bug.
>> $this->_str .= $string;
>> )
>> function show()
>> {
>> return $this->_str;
>> }
>>}
>>
>>class B
>>{
>> function B()
>> {
>> $debug = &new DebugHelper;
>> $debug->do('here');
>> ...
>> }
>>}
>
>
> create a debug function (public) and use get_class. call that in the

if you are using the 'public' keyword then you have to use php5,.....

> debug function. when u want to do the debugging, use it with the obj
> as parameter, maybe $this will work when u're in the class, otherwise,
> use the object aka class instance variable.
>
> u may wanna pass by reference and make it const (won't have to use

if you're using php5 all objects are references, pass-by-reference occurs
whether you like it or not (unless you specifically use 'clone')

....also a constant (global or class scope) cannot be set to an object.

I'm still very curious as to how Yangshiqi intends to use his DebugHelper class!
(apologies if I have written your name incorrectly.)


> more memory for it...since it's task with it is small and read-only)
>
> from http://php.net/get_class
> [quote]
> Example 1. Using get_class()
> <?php
>
> class foo {
> function foo()
> {
> // implements some logic
> }
>
> function name()
> {
> echo "My name is " , get_class($this) , "\n";
> }
> }
>
> // create an object
> $bar = new foo();
>
> // external call
> echo "Its name is " , get_class($bar) , "\n";
>
> // internal call
> $bar->name();
>
> ?>
>
> The above example will output:
>
> Its name is foo
> My name is foo
> [/quote]
>

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