Posted by M. Sokolewicz on 10/04/87 11:10

Jochem Maas wrote:
> Robert Janeczek wrote:
>
>> YaronKh@clalit.org.il wrote:
>>
>>> Hi It is an expected behavior because when you define a static
>>> variableit is shared by all objects of the same class. If When you
>>> unset one object and the destruct of the static object will be
>>> called, all the other objects will lose the static var as well.
>>
>>
>>
>> yes, but why destuctor isn`t called after all the execution is
>> finished? i mean the moment when php does clean up before it finishes
>> to process request?
>
>
> oh boy this is tricky water, you might want to search the php-internals
> archive
> for threads where this is discussed in some detail - in short:
>
> don't expect anything to output at shut down time. and don't
> rely on objects/resources existing if a dtor is called when php is
> cleaning up.
> basically you can't rely on much at all in a dtor if you are letting php
> call
> the dtor at 'shutdown' (sorry if my terminology is off rgd the termination
> process of a php instance)
>
>>
>> rash
>>
Actually, my understanding of this is as follows:
a static variable is a "variable" (more like a constant) which is a part
of a class (*not* an object!). Were it a normal member, it would be part
of an object (and not just the class), and would be destroyed when the
object was destroyed. However, you're using a *class* and not an
*object*, so PHP will never call the destructor since it's not working
with an object it can destroy.

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