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Posted by Petr Smith on 10/29/05 22:19
Hi,
why don't you use normal php include (require) functions? Why do you
want to mix apache server side includes with php code? There is nothing
php include can't do..
Just change all
<!--#INCLUDE virtual="xxxx"-->
to
<? include('xxxx'); ?>
Petr
Don Brown wrote:
> We're having a problem getting more than one imbedded PHP script to execute in our Apache-served pages. We're using Apache 2.0.40 server-side includes. We wish to include multiple PHP scripts into our pages but are only succeeding in having the first included PHP script executed; the rest are ignored or misinterpreted as HTML...
>
> Thank you in advance for any help you provide.
>
>
> This works:
>
> $ cat php1.txt
> <?php
> echo "this is the first php include";
> ?>
> $ cat test.shtml
> <html><body>
>
> <!--#INCLUDE virtual="/php1.txt"-->
>
> <br>this came from html
>
> </body></html>
>
> Producing the expected result from the browser (http://myhost/test.shtml):
> this is the first php include
> this is html
>
> However, this does not produce the expected three line result:
>
> $ cat php1.txt
> <?php
> echo "this is the first php include";
> ?>
> $ cat php2.txt
> <?php
> echo "this is the second php include";
> ?>
> $ cat test.shtml
> <html><body>
>
> <!--#INCLUDE virtual="/php1.txt"-->
> <br>
> this came from html
> <br>
> <!--#INCLUDE virtual="/php2.txt"-->
>
> </body></html>
>
> Producing from the browser (http://myhost/test.shtml):
> this is the first php include
> this is html
>
>
> This DOES work:
>
> $cat test.php
> <html><body>
>
> <?php
> echo "this is from the first php block";
> ?>
>
> <br>
> this is from html
> <br>
>
> <?php
> echo "this is from the second php block";
> ?>
>
> </body></html>
>
> Producing from the browser (http://myhost/test.shtml):
> this is from the first php block
> this is from html
> this is from the second php block
>
>
> Don Brown
> Co-Founder, Utah Skies
> "Ski champagne powder by day, surf diamond-studded velvet by night..."
>
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