Posted by Rasmus Lerdorf on 09/25/64 11:11

PartyPosters wrote:
> Hello,
> Please could someone tell me why I am getting (Notice: Undefined offset: 3 in ..........) from using this code.
>
>
> for ($i=0; $i<=3; $i++){
> mysql_query("INSERT INTO shipped(userID, productID, distID, username,ship_company, ship_add1,ship_add2) VALUES(1, '$productID','$v_distIDArray[$i]', userID, '$v_companyArray[$i]','$v_add1Array[$i]','$v_add2Array[$i]')");
> }

Because you only have 3 elements in one or more of those arrays.
Remember, index 3 is the 4th element.

-Rasmus

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