Reply to Re: [PHP] Replacement Question.

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Posted by Bob Palma on 04/20/05 18:01

Wow! Thanks.. That works great. Just one small hitch though. After it
prints all of the data properly, it adds one more '$date' on the end
which gets printed as '12/31/69 7:00:pm'. Is there a way to do all
groups - 1 ?

Bob Palma
bpalma@ciber.net

Duncan Hill wrote:

> On Wednesday 20 April 2005 15:22, Bob Palma typed:
>
>>I have a database field that I need to read and do some conversion on.
>>Here is what the raw data from the database looks like:
>>
>>--
>>1084751309jpenaDisney Vignette Fleximon disk utilization
>>alert C:\ at 85%1084799703bpalmafixed.1084799713bpalmaclosed
>>--
>
>
> Are the group delimiters different from the field delimiters?
>
> Ie, can you do:
> $array_of_groups = explode('group_delim', $in_string);
> foreach ($array_of_groups as $i) {
> $array_of_fields = explode('field_delim', $i);
> $date = date('m/j/y g:i:a', $array_of_fields[0]);
> print "$date {$a_o_f[1]}<br />{$a_o_f[2]}<br /><br />\n";
> }
>
> YMMV of course.
>

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