Posted by Marek Kilimajer on 04/28/05 15:26

Bostjan Skufca @ domenca.com wrote:
> function add ($a=1, $b=2, $c=3) {
> return $a + $b + $c;
> }
> add(1, null, 1);
>
> will do just fine

returns 2, OP wants 4 IMO


>
> r.,
> Bostjan
>
>
>
> On Thursday 28 April 2005 14:16, Marek Kilimajer wrote:
>
>>Vedanta Barooah wrote:
>>
>>>Hello All,
>>>Cosider this :
>>>
>>>function add($a=1,$b=2,$c=3){
>>> return $a + $b + $c;
>>>}
>>>
>>>how do i skip the second argument while calling the function, is there
>>>a process like this:
>>>
>>>echo add(1,,1); # where i expect 2 to be printed,
>>
>>php does not support this. you can workaround this using:
>>
>>function add($a = null,$b = null, $c = null){
>> if(is_null($a)) $a = 1;
>> if(is_null($b)) $b = 2;
>> if(is_null($c)) $c = 3;
>> return $a + $b + $c;
>>}
>>
>>add(1, null, 1);
>
>

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