Reply to Re: very simple drop-down list...

Your name:

Reply:


Posted by mars on 09/19/05 17:52

max probably wrote the following stuff on 19/09/2005 1.04:
> Hi! I'm having a problem with a very simple drop-down list since the
> page comes out with no elements in the drop-down but giving no errors.
> This is the code:
>
>
> <form name="year_search_form" method="post" action="results.php">
> <select name="select_year" id="select_year">
> <?
> $query="SELECT * FROM table ORDER BY year";
> $result = mysql_query($query) or die ("Error in query: $query. "
> .mysql_error());
>
> while ($line = mysql_fetch_array($result)) {
> print ("<OPTION value=".$line['year']."></OPTION>"); }
> ?>
> </select>
> </form>
>
> The connection with the DB is established and working..
> Thanks for your help!!


Fixed it! The main problem were the quotes :

print ('<OPTION value="'.$line['year'].'">'.$line['year'].'</OPTION>');

here it works.
Thanks!

[Back to original message]


Удаленная работа для программистов  •  Как заработать на Google AdSense  •  England, UK  •  статьи на английском  •  PHP MySQL CMS Apache Oscommerce  •  Online Business Knowledge Base  •  DVD MP3 AVI MP4 players codecs conversion help
Home  •  Search  •  Site Map  •  Set as Homepage  •  Add to Favourites

Copyright © 2005-2006 Powered by Custom PHP Programming

Сайт изготовлен в Студии Валентина Петручека
изготовление и поддержка веб-сайтов, разработка программного обеспечения, поисковая оптимизация