Reply to Re: exec("ls *.*") gives unexpected output

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Posted by Chris Hope on 11/24/07 11:28

kurt.krueckeberg@gmail.com wrote:

> The second line of this script
> <?php
> // current directory
> echo getcwd() . "<br />";
> print ( exec("ls *.*") );
> ?>
> should display the names of the four files (it does in an ssh session)
> which are located in public_html, but instead it displays just one
> filename, that of this script.
>
> I don't understand why?

It would be a good idea to refer to the manual:
http://www.php.net/manual/en/function.exec.php

Note in particular:
"Return Values
The last line from the result of the command. If you need to execute a
command and have all the data from the command passed directly back
without any interference, use the passthru() function."

--
Chris Hope | www.electrictoolbox.com | www.linuxcdmall.com

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