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Posted by Mark Sargent on 05/10/05 07:23
Hi All,
this page,
http://www.freewebmasterhelp.com/tutorials/phpmysql/5
has the below code,
<?
$i=0;
while ($i < $num) {
$first=mysql_result($result,$i,"first");
$last=mysql_result($result,$i,"last");
$phone=mysql_result($result,$i,"phone");
$mobile=mysql_result($result,$i,"mobile");
$fax=mysql_result($result,$i,"fax");
$email=mysql_result($result,$i,"email");
$web=mysql_result($result,$i,"web");
?>
<tr>
<td><font face="Arial, Helvetica, sans-serif"><? echo $first." ".$last;
?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><? echo $phone; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><? echo $mobile;
?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><? echo $fax; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><a href="mailto:<? echo
$email; ?>">E-mail</a></font></td>
<td><font face="Arial, Helvetica, sans-serif"><a href="<? echo $web;
?>">Website</a></font></td>
</tr>
<?
$i++;
}
echo "</table>";
which I basically understand, except the html generation. I am trying to
create something similiar, although, I think there are some errors in
even perhaps my logic..?
<html>
<body>
<h1><center>Jumbo Status</center></h1><br>
<?php
$db = mysql_connect("localhost", "root", "grunger");
mysql_select_db("status",$db);
$result = mysql_query("SELECT ProductTypes.product_type_detail FROM
ProductTypes",$db);
$myrow = mysql_fetch_array($result);
$num = mysql_num_rows($result);
?>
<table aligh="center" border="2">
<tr>
<td>Product Type</td>
</tr>
<?
$i=0;
while ($i < $num){
$product_type=mysql_result($result,$i,"product_type_detail");
echo "<tr><td><? echo $product_type ?></td></tr>"
}
$i++
?>
</table>
</body>
</html>
I get the folowing error,
*Parse error*: parse error, unexpected '}', expecting ',' or ';' in
*/var/www/html/products.php* on line *20
*
which is the $i++ section.
Cheers.
Mark Sargent.
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