Posted by barbarowa on 02/06/06 16:59

I think I need to clarify what my objective is. Despite the code that
I posted which my attempt to test what is actually getting passed to
the program from the drop down menu selection, what I REALLY want is
to know HOW to pass the variable the correct way and then how to use
it in a MySQL INSERT statement. I tried the code you provided and
this is what is shown: $_POST: Array ( )

I know an array is what I'm up against, what I don't know is how to
deal with it. Does this help clear up what I am looking for?



On Mon, 06 Feb 2006 10:09:43 +0100, Iván Sánchez Ortega
<i.punto.sanchez--@rroba--mirame.punto.net> wrote:

>-----BEGIN PGP SIGNED MESSAGE-----
>Hash: SHA1
>
>barbarowa@yahoo.com wrote:
>
>>>And why exactly are you mixing $_POST and $HTTP_POST_VARS?
>>
>> Just hoping to see what variable values are being passed.
>
>Then use something like:
>
><?php
>
>if (isset($_POST))
>{
> echo '$_POST: '; print_r($_POST); exit;
>}
>else if (isset($HTTP_POST_VARS))
>{
> echo '$HTTP_POST_VARS: '; print_r($HTTP_POST_VARS); exit;
>}
>
>?>
>
>Think about:
>- - What if $_POST gets a value but $HTTP_POST_VARS does not? (and the other
>way round)
>- - What if $_POST['testform'] gets a value of 0, oran empty string, that will
>evaluate as false?

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