Posted by Jerry Stuckle on 02/06/06 18:36

barbarowa@yahoo.com wrote:
> I think I need to clarify what my objective is. Despite the code that
> I posted which my attempt to test what is actually getting passed to
> the program from the drop down menu selection, what I REALLY want is
> to know HOW to pass the variable the correct way and then how to use
> it in a MySQL INSERT statement. I tried the code you provided and
> this is what is shown: $_POST: Array ( )
>
> I know an array is what I'm up against, what I don't know is how to
> deal with it. Does this help clear up what I am looking for?
>
>

Looks like you did:

echo '$_POST: '; print($_POST); exit;

Instead of

echo '$_POST: '; print_r($_POST); exit;
^^

For an array, print() will print "Array()";

print_r() will print the contents of an array.

You should find the value from the previous form in $_POST['id'].

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
==================

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