Posted by d on 09/26/21 11:39

"Fred Paris" <nono@nono.invalid> wrote in message
news:mr5ku1dpuaiukdi9j85t8b002v5lepn8qm@4ax.com...
> Hi
>
> I would like to know if the following is possible and how to do it:
>
> 1)
> I have a "template" .php file on my server, say template.php.
> It contains some PHP instructions and some HTML
>
> 2)
> I also have a script, script.php
>
> 3)
> When script.php runs, I want it to run php on template.php, and write
> the resulting html output to a file.
>
> I need to say something like:
>
> <?php
>
> runphp ( 'template.php', 'htmloutput.html' );
>
> ?>
>
> and obtain a file, htmloutput.html, with the result of php having run
> template.php (hope I'm being clear).
>
> The problem is, of course, that the runphp function doesn't exist so
> what is the way to do it?
>

function runphp($in_fn, $out_fn) {
ob_start();
include($in_fn);
$c=ob_get_contents();
ob_end_clean();
$fp=fopen($out_fn, "wb");
fwrite($fp, $c);
fclose($fp);
}

That's very simple, of course. If something isn't exactly right in how it's
called, it'll fail most spectactularly :) It gives you the general jist,
though - using output buffering to capture the output of a given script, and
then storing that output in a file.

Let me know if there's something you don't understand.

dave


> Thanks
> Fred
>

[Back to original message]