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Posted by tmax on 02/15/06 02:55
Thank You Dave!!!
This code works - I used ob_start() to get around some header() errors,
but after implementing that, my form and page works exactly as I
intended it to. Learned quite a bit from all of this too. Thanks again!
Travis
d wrote:
> "tmax" <tmax@comcast.net> wrote in message
> news:1f9bd$43f23b15$481a8e8e$29885@PGTV.COM...
>
>>Well, I've tried everything that has been suggested so far - thanks for
>>everyone's input.
>>
>>However, let me restate the problems differently as I believe it wasn't
>>correct to begin with.
>
>
> I understand completely what you're asking :)
>
> Try this code:
>
> <?
>
> session_start();
>
> if (isset($_POST["data"])) {
> $_SESSION["data"]=$_POST["data"];
> session_write_close();
> header("Location: ".$_SERVER["SCRIPT_URI"]);
> exit();
> }
>
> if (isset($_SESSION["data"])) {
> ?>
> <html>
> <head><title>Thanks!</title></head>
> <body>
> Thank you for submitting your data:<br>
> <?=$_SESSION["data"];?>
> </body>
> </html>
> <?
> } else {
> ?>
> <html>
> <head><title>Please Submit</title></head>
> <body>
> Use the form to submit your data:<br>
> <form method="post">
> <input type="text" name="data"><br>
> <input type="submit" value="Go!">
> </form>
> </body>
> </html>
> <?
> }
> ?>
>
> It will show a form, and take that posted data and store it in a session.
> Then, the script re-directs you back to itself, and that redirection stops
> your browser wanting to resubmit the data when refreshed. The session is
> then checked, and if the data is present, a thank-you note is displayed. If
> not, it then shows the initial form.
>
> dave
>
>
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