Posted by Bernhard Kraft on 10/04/42 11:06

Bob wrote:

> :User enters 040 in field uinput on form
> :
> :print $_POST['uinput'] * 2;

PHP does not automatically recognize the base in which numbers are
given ...
when it does string-2-integer conversion as it takes place in your example:
$_POST['uinput'] * 2
($_POST['uinput'] gets converted to a number) it will always asume your
number to be in base-10

you can do base conversions using:
string base_convert ( string number, int frombase, int tobase)

http://at2.php.net/manual/en/function.base-convert.php

but you will have to check with your code if the number is in
octal (preceeding 0) or in hexadecimal (preceeding 0x) or other
bases ...


greets,
Bernhard

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