Reply to could use some help with my login script

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Posted by Greg on 10/19/05 23:08

I'm not new to the login script, however I'm trying to do it with Classes,
which I am new too. Two pages involved, login.php and clsLoginForm.php .

The login.php file submits to itself, it the values are not defined the form
is shown, (this part works fine) and if the values are found checks the
database for a match and redirects.

The login.php file looks like this:

<?
$username = $_POST['username'];
$userpassword = $_POST['userpassword'];

if (empty($_POST['username']) || empty($_POST['userpassword'])){

$showform = &new LoginForm;
echo $showform->showform();
}
else
{

$login = &new LoginForm;

$login->username = "$username";
$login->userpassword = "$userpassword";

$login->userlogin();

}
?>




The clsLoginForm.php class looks like this. The problem is with my sql
context look for //THIS IS WHERE THE PROBLEM IS below:




<?

class LoginForm{

function showform()
{

// define the submission to self

$self = $_SERVER['PHP_SELF'];

// Create the Form

$form = "<form method=\"post\" action=\"$self\">\n";
$form .= "<table width=\"100%\" align=\"center\">\n";
$form .= "<tr>\n";
$form .= "<td width=\"30%\" align=\"right\">Username:</td><td
align=\"left\"><input type=\"text\" value=\"" . $_POST['username'] . "\"
name=\"username\"></td>\n";
$form .= "</tr>\n";
$form .= "<tr>\n";
$form .= "<td align=\"right\">Password:</td><td align=\"left\"><input
type=\"password\" value=\"" . $_POST['userpassword'] . "\"
name=\"userpassword\"></td>\n";
$form .= "</tr>\n";
$form .= "<tr>\n";
$form .= "<td></td><td align=\"left\"><input type=\"submit\"
class=\"formsubmit\" name=\"submit\" value=\"Login\"></td>\n";
$form .= "</tr>\n";
$form .= "</table>\n";
$form .= "</form>\n";

// Show the form

return $form;
}

function userlogin()
{
include $_SERVER['DOCUMENT_ROOT'] . "/includes/dbconnect_admin.php";

/* These are unused variables. I was trying it this way when it wasn't
working before
$username = $this->username;
$userpassword = $this->userpassword;*/

// THIS IS WHERE THE PROBLEM IS

$sql = "SELECT * FROM users WHERE username=$this->username AND
password=$this->userpassword";

// END PROBLEM

$results = mysql_query($sql);
$dbdata = mysql_fetch_array($results);
$row = mysql_num_rows($results);

if ($row == NULL){

$showform = &new LoginForm;
echo $showform->showform();
}
else
{
session_start();
$_SESSION['fname'] = $dbdata["fname"];
$_SESSION['lname'] = $dbdata["lname"];
header ("Location: http://www.somesite.com");
exit();
}

}
}
?>

The Error i'm getting is:

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in /home/berrock/public_html/classes/clsLogin_Form.php on line 42

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result
resource in /home/berrock/public_html/classes/clsLogin_Form.php on line 43

Any ideas? Thanks in advance for any help.

Greg

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