Posted by comp.lang.php on 11/18/28 11:42

if ($willLimitByDB) $sql = preg_replace('/#([^#]+)#/i', '$$1',
$sql);

This does not give me the results I want, instead of the value of
$where in $sql, I literally get '$where' instead.

How do I substitute #where# with $where?

Thanx
Phil

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