Reply to Re: What does "Call to a member function on a non-object" mean?

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Posted by Stephen Kay on 03/24/06 23:59

in article e00cln$l81$1$8300dec7@news.demon.co.uk, Tony Marston at
tony@NOSPAM.demon.co.uk wrote on 3/24/06 4:03 AM:

> This is because you are doing something like
> $result = $object->function($arg);
> and $object is not an actual object. Perhaps you have not initialised it
> yet, or miss-spelled it?

Thanks for the info. It seems there was an uninitialized object in an
included file.

Stephen

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