Reply to imagecreatefromjpeg, calling a .php file

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Posted by Areric on 04/16/06 09:01

Ok all. I have a series of images stored in a db. Im trying to work on
a script that will let me scale them based on user input. Ive hit a bit
of a roadblock on this line.

$orig =
imagecreatefromjpeg("DisplayImage.php?imageId=".$this->mImage->GetImageId());

Specifically it cant sopen that file.

DisplayImage.php is pretty simple, it just displays an image from the
db without writing to a file.

Im thinking the problem is in how im pathing to DisplayImage.php.

This file sits one level lower than most things so it should be
.../displayImage, but i tried that and no luck.

Any ideas whats wrong with that line?

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