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Posted by robert on 10/14/43 11:45
| The solution is:
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| select grad_pbroj, Naziv, COUNT(*) as brojac from smjestaj left join grad
on
| grad.grad=smjestaj.grad_pbroj group by grad_pbroj order by grad_pbroj ASC
i don't think so...that should cough up a nasty error as "naziv" is not
handled in the group by clause nor is it part of an aggrigate function...and
that's just me eye-balling it for .5 seconds.
btw...people who DONT format their inline sql should be shot! which is more
manageable, the above or:
SELECT s.grad_pbroj ,
s.Naziv ,
COUNT(*) brojac
FROM smjestaj s
LEFT JOIN grad g ON
g.grad = s.grad_pbroj
GROUP BY s.grad_pbroj ,
s.Naziv
ORDER BY s.grad_pbroj ASC
** and if this query is to return the number of duplicates, then there
should either be a where or having clause that only returns a row if the
count is > 1.
but that's just me following real-world, professional standards. the former
should just be all on one line for christ' sake.
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