Posted by lawrence k on 05/22/06 08:18

lawrence k wrote:
> I've two functions. currentHeadline looks in $_GET for a variable
> called 'image' and prints what it finds. showThumbnail takes an image
> for a parameter and resizes it before sending it to the screen. But
> when I do this:
>
> <?php showThumbnail(currentImage(), 20, 20); ?>
>
> showThumbnail is telling me that it is not being given a file name, and
> currentImage is printing the file name to the screen. How is that
> possible? What is the right way to do this?

Nevermind, I'm an idiot. currentImage was echoing its result to the
screen instead of returning it.

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