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Re: A basic question: Removing duplicate results from Max function

Posted by David Portas on 06/10/06 19:05

aamircheema@gmail.com wrote:
> Hi,
>
> Say I have a table Job with columns name, date, salary . I want to get
> the name ,date and salary for the date when that person earned maximum
> salary. I am using something like
>
>
> SELECT X.name,X.date,X.salary
> FROM job X
> WHERE X.salary IN
> (SELECT MAX(Y.salary) FROM job Y where Y.name= X.name);
>
>
> The problem is ; if a person earns maximum salary on two dates, both of
> the dates are printed. I just want to get any one of those two rows.
> I tried
>
> SELECT X.name,Min(X.date),X.salary
> FROM job X
> WHERE X.salary IN
> (SELECT MAX(Y.salary) FROM job Y where Y.name= X.name);
>
> but it gives error.
> Can anybody please suggest a solution?
>
> Regards,
> Aamir

In SQL Server 2005:

WITH j AS
(SELECT name, date, salary,
RANK() OVER (PARTITION BY name ORDER BY salary DESC, date DESC) rnk
FROM job)
SELECT name, date, salary
FROM j
WHERE rnk = 1 ;

That assumes the combination of (name,salary,date) is unique. If it
isn't then just add other columns to the ORDER BY specification to make
a key.

--
David Portas, SQL Server MVP

Whenever possible please post enough code to reproduce your problem.
Including CREATE TABLE and INSERT statements usually helps.
State what version of SQL Server you are using and specify the content
of any error messages.

SQL Server Books Online:
http://msdn2.microsoft.com/library/ms130214(en-US,SQL.90).aspx
--

 

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