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Re: Challenge: MySql result to drop down box

Posted by Jim S on 07/13/06 16:01

I think I have narrowed it down to the for loop causing the problem...

Jim S wrote:
> I have made the two changes you suggested but am still not receiving a
> result set. Let me repost my modified code.
>
> <?php
> $res=mysql_query("SELECT DISTINCT job_name FROM
> oats_jobs_users_laborCode where user='$username' order by job_name");
> echo "<select name=jobname> <option default='default'>Choose
> One</option>";
> for ($i=0; $row=mysql_fetch_row($res); $i++)
> {
> echo "<option value='$row[0]'>$row[0]</option>";
> }
> echo "</select>";
> ?>
>
> And thank you for the mysql_fecth_rows command--it was helpful in other
> places as well :-)
>
> Rik wrote:
>> And now I see this:
>>
>>>> echo "<option value='<? echo $row[0];?>'><? echo
>>>> $row[0];?></option>";
>>
>> That will not echo what you want it to echo.
>> Think about it, <?php ?> tags aren't nestable, why should they?
>>
>> echo "<option value='$row[0]'>$row[0]</option>";
>>
>> Grtz,

 

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