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Posted by Techris on 10/14/48 11:53
BTW the file was saved as index.php thus the form action.
"Techris" <tedkac@ubtanet.com> wrote in message
news:12c21eu1d0hqhef@corp.supernews.com...
> Can anyone tell me why this isn't working.. I am sure its just something
> stupid but I can't see it yet.
>
> <?PHP
>
> function uploadpic($pic){
> foreach($pic as $value){
> copy ($_FILES['$value']['tmp_name'], $_FILES['$value']['name'])
> or die ("Could not copy");
>
> echo "<img width=\"100\" src=
> \"".$_FILES['$value']['name']."\"<br><br><br>";
> echo "Name: ".$_FILES['$value']['name']."<br>";
> echo "Size: ".$_FILES['$value']['size']."<br>";
> echo "Type: ".$_FILES['$value']['type']."<br>";
> echo "Upload Done....<br>";
> }
> }
>
> if(!empty($pic) && $mode == "uploadpic")
> {
> uploadpic($pic);
> }
> else {
> echo "<form name=\"form1\" method=\"post\"
> action=\"index.php?mode=$mode&pic=$pic\"><br>";
> echo "First Picture:<input type=\"file\" name=\"$pic[0]\"><br>";
> echo "Second Picture:<input type=\"file\" name=\"$pic[1]\"><br>";
> echo "Third Picture:<input type=\"file\" name=\"$pic[2]\"><br>";
> echo "Fourth Picture:<input type=\"file\" name=\"$pic[3]\"><br>";
> echo "Fifth Picture:<input type=\"file\" name=\"$pic[4]\"><br>";
> echo "<input type=\"hidden\" name=\"mode\" value=\"uploadpic\">";
>
> echo" <br>
> <br><br>
> <input type=\"submit\" name=\"submit\" value=\"Submit\">
> ";
> echo "</form>";
> }
> ?>
>
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