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Posted by -Lost on 10/11/95 11:53
"ClickToWalk" <admin@clicktowalk.com> wrote in message
news:44bfb933$1_4@mk-nntp-2.news.uk.tiscali.com...
> This is a bit of code that I have used to successfully echo all the available records -
> with gaps where records are missing - but what modifications do I need to make to it so
> that only one row is returned from the recordset, determined by $id.
You could throw an if clause in checking the number of rows returned (mysql_num_rows) or
even possibly check with mysql_affected_rows (assuming an INSERT, DELETE, or UPDATE).
You could also LIMIT your results and output those three rows [previous, current, next].
Lastly, your query function could do the same as the above, but then also check to see if
they are valid results. This you could add to your existing code...
-Lost
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