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Posted by Noodle on 07/26/06 09:04
Bob Stearns wrote:
> Noodle wrote:
>
> > Bob Stearns wrote:
> >
> >>Am I conflating PHP with another language (PERL maybe?) or can you do an
> >>assignment to $a, $b and $c something like ($a, $b, $c) = $array? The
> >>given sytax doesn't work nor does [$a, $b, $c] = $array. This leads me
> >>to believe in the conflation theory. If there is a syntax for this,
> >>could you please send me a manual reference for it?
> >
> >
> > $array = array($a, $b, $c);
> >
> > http://www.php.net/manual/en/function.array.php
> >
> That is the opposite of what I wanted. The correct syntax, as pointed
> out by Andy Hassal is:
>
> list($a, $b, $c) = $array;
Fair Enough. I don't think I read your question correctly.
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