Posted by walterbyrd on 12/17/88 11:54

I know I can use the file() function to read a file into an array by
providing a literal file name between single quotes:

$lines = file('literal_file_name');

But, what if I want file() to use a variable name?

$variable_file_name = "literal_file_name";
$lines = file($variable_file_name);

Of course, that example won't work. But what will?

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