Posted by lawrence k on 08/17/06 19:48

I've this class method, which makes sure I've got a variable that is a
resource:

function close() {
if (is_resource($this->datastoreResultsPointer)) {
mysql_free_result($this->datastoreResultsPointer);
mysql_close();
}
}

all the same, I'm getting these PHP errors:


Warning: mysql_free_result(): 286 is not a valid MySQL result resource
in
/home/httpd/vhosts/monkeyclaus.org/httpdocs/media/audio/pdsIncludes/McDatastoreResultsMySql.php
on line 89

Warning: mysql_close(): no MySQL-Link resource supplied in
/home/httpd/vhosts/monkeyclaus.org/httpdocs/media/audio/pdsIncludes/McDatastoreResultsMySql.php
on line 90


How is that possible?

• Next in forum: Re: Why no television programmes about php ?
• Prev in forum: Re: PHP4 -> PHP5 issue
• Thread view: even after proper error checking, I still get PHP warnings

[Reply to this message]