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Re: parsing template using preg_replace_callback()

Posted by mens libertina on 08/18/06 01:37

Jerry Stuckle wrote:
> mens libertina wrote:
> > After I read your post, I declared $info as "$info = array();" at the
> > top of the program with the same result. Did I misunderstand what you
> > meant by global scope?
>
> But now your problem is $info in the function is not the same as $info
> in the main program.
>
> When declared as a parameter like this, $info is only local to the
> function. Any other $info is completely separate from the one in the
> function.

Ugh. So if I can't pass by reference, what options do I have? It
sounds like I can't use preg_replace anywhere but the main body...

<about to throw mouse!>

 

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